The two colours mentioned in this question are blue and white. Let us assume the third colour to be black. Statement 1: Nayan has 2 white caps Given: Nayan has 4 caps of 3 “different” colours. Thus, we have the following combination: Case 1) 2 white caps and 1 blue cap [ alt="F1 Archana 30-12-21 Saivita D1" src="//storage.googleapis.com/tb-img/production/21/12/F1_Archana_30-12-21_Saivita_D1.png" style="width: 311px; height: 42px;"> Case 2) 2 white caps and 2 blue caps. [ alt="F1 Archana 30-12-21 Saivita D2" src="//storage.googleapis.com/tb-img/production/21/12/F1_Archana_30-12-21_Saivita_D2.png" style="width: 311px; height: 42px;"> This is not possible as 4 caps should have 3 different colours. Case 3) 2 white caps and 2 black caps [ alt="F1 Archana 30-12-21 Saivita D3" src="//storage.googleapis.com/tb-img/production/21/12/F1_Archana_30-12-21_Saivita_D3.png" style="width: 311px; height: 42px;"> This is not possible as 4 caps should have 3 different colours. Thus, we can eliminate cases 2 and 3. Therefore, Nayan has 1 blue cap. Hence, statement 1 alone is sufficient to answer the question. Statement 2: The number of blue caps he has is the same as that of white caps. Case 1) 1 white cap and 1 blue cap This will imply that the remaining 2 caps are black [ alt="F1 Archana 30-12-21 Saivita D4" src="//storage.googleapis.com/tb-img/production/21/12/F1_Archana_30-12-21_Saivita_D4.png" style="width: 311px; height: 42px;"> Case 2) 2 white caps and 2 blue caps. This case is not possible because there should be 3 different colours. Therefore, Nayan has 1 blue cap. Hence, statement 1 alone is sufficient to answer the question. Hence, statement 1 or 2 alone is sufficient to answer the question.