Given: Tony purchases two cars A and B at a total cost of Rs. 6,50,000. He sells car A with 20% profit and car B at a loss of 25% and gets the same selling price for both the cars Concept used: SP = (100 + profit%)/100 × CP = (100 - loss%)/100 × CP Calculation: ∴ For Car A, SP1 : CP1 = (100 + 20) : 100 = 120 : 100 = 6 : 5 and for Car B, SP2 : CP2 = (100 - 25) : 100 = 75 : 100 = 3 : 4 Now, given SP1 = SP2 ∴ On making equal, we get, SP1 : CP1 = 6 : 5 and SP2 : CP2 = 6 : 8 ⇒ CP1 : CP2 = 5 : 8 and total cost of car A and car B is Rs. 6,50,000 ∴ Cost of car A = 5/13 × Rs. 6,50,000 = Rs. 2,50,000 and Cost of car B = 8/13 × Rs. 6,50,000 = Rs. 4,00,000