Three rigid buckets, shown as in the figures (1), (2) and (3), are of identical heights and base areas. Further, assume that each of these buckets have negligible mass and are full of water. The weights of water in these buckets are denoted as W1, W2, and W3 respectively. Also, let the force of water on the base of the bucket be denoted as F1, F2, and F3 respectively. The option giving an accurate description of the system physics is Correct Answer W2 > W1 > W3 and F1 = F2 = F3 Explanation: Given, [ alt="F1 21-09-21 Chandramouli Savita D3" src="//storage.googleapis.com/tb-img/production/21/09/F1_21-09-21_Chandramouli_Savita_D3.png" style="width: 344px; height: 162px;"> Identical Heights and Base Areas. i.e. Area = Constant, Height = Constamt We know Force on base is given by F = γ A H as Area and height are constant, Force acting in each base is constant. Therefore, F1 = F2 = F3 Coming to weight. Weight is given by W = ρ × g × (Volume) So weight id proportional to Volume Volume of container in (Bucket 2) > Bucket 1 > Bucket 3 Therefore, W2 > W1 > W3