The following question, there are three statements I, II and III. Read the question carefully and mark your answer according to which statements(s) is/are sufficient to the answer the question. Find the probability that both the balls are of blue color. Statement I: In a bag containing 4 red balls, 6 blue balls and 8 yellow balls, two balls are drawn at random one by one without replacement. Statement II: First ball is blue and if this happens then 5 more blue balls are added in the bag Statement III: Total blue balls are twice more than the other balls at the end of the drawing of balls Correct Answer Only I and II From statement I and II Probability of first ball to be blue = 6C1/18C1 Probability of the second ball turns out to be blue with the given condition = 10C1/22C1 Required probability = (6C1/18C1) × (10C1/22C1) = 5/33 ∴ Only I and II are required and statement III do not give any proper relation and will not help in solving