Given: Circumference of the base of circular cylinder = 12π cm. Height of the cylinder = Diameter of the cylinder Diameter of the spherical balls = 3 cm Concept used: Diameter = 2 × radius Circumference of the base of circular cylinder = 2πr → r = radius of the cylinder Volume of the cylinder = πr2h → r = radius of cylinder → h = height of cylinder Volume of the sphere = (4/3)πR3 → R = Radius of the sphere Volume of the cylinder = Number of balls × Volume of each spherical ball Calculations: Circumference of the base of circular cylinder = 2πr ⇒ 12π = 2πr ⇒ r = 6 Height of the cylinder = 2r = 12 Volume of the cylinder = πr2h ⇒ π × 6 × 6 × 12 ⇒ 432π Radius of each spherical ball = Diameter/2 = 3/2 cm. Volume of each spherical ball = (4/3)πR3 ⇒ (4/3) × π × (3/2)3 Volume of the cylinder = Number of balls × Volume of each spherical ball ⇒ 432π = Number of balls × (4/3) × π × (3/2)3 ⇒ 432 = Number of balls × 4/3 × 3/2 × 3/2 × 3/2 ⇒ 96 = Number of balls ∴ The number of balls = 96