Given: Quantity of water is twice the quantity of honey Quantity of water initially = 300ml Solution: Quantity of water initially = 300ml ∴ Quantity of honey in the mixture = 300/2 = 150 ml Now, 'x' ml of mixture is taken out and 80 ml of honey is added the ratio becomes 21 ∶ 26 Quantity of honey left = 150 – x × (150/450) + 80 = 230 – x/3 Quantity of water left = 300 – x × (300/450) = 300 – 2x/3 ∴ (230 – x/3)/(300 – 2x/3) = 21/26 ⇒ (690 – x)/(900 – 2x) = 21/26 ⇒ 17490 – 26x = 18900 – 42x ⇒ 16x = 960 ⇒ x = 60 ∴ 60 ml of mixture is taken out Quantity of honey = 230 – (60/3) = 230 – 20 = 210 Quantity of water = 300 – (120/3) = 300 – 40 = 260 Now, '2x' ml of honey is added in the mixture ∴ Quantity of honey = 210 + 120 = 330 Quantity of water = 260 ∴ Required ratio = 330/260 = 33/26 ∴ The ratio of honey and water in the final mixture is 33 ∶ 26