Given: Area of rhombus = 24 cm2 Let one diagonal be x cm and the other be (x + 2) cm Calculation: Let us consider Statement I, With the help of this statement alone, we cannot arrive at a solution. Now, let us consider statement II, We know, Area = (1/2) × (d1 × d2) ⇒ 24 = (1/2) × (x ) × (x + 2) ⇒ 48 = x2 + 2x ⇒ x2 + 2x - 48 = 0 ⇒ x = 6, - 8 (length cannot be negative) Length of the diagonal is 6 cm and x + 2 = 8 cm That is, with statement II alone we can reach the solution. ∴ Only statement II is required. Or we can calculate it like this Area = (1/2) × (d1 × d2) ⇒ 24 = (1/2) × (x ) × (x + 2) 48 = x2 + 2x = x × (x + 2) ⇒ 6 × 8 = 6 × (6 + 2) = x × (x + 2) ⇒ x = 6 ⇒ Diagonals are 6 and 8 ∴ Only statement II is required.